Solve Using the Square Root Property y^2-4y=0

$y^{2} - 4 y = 0$

Step 1

Factor $y$ out of $y^{2} - 4 y$ .

Factor $y$ out of $y^{2}$ .

$y \cdot y - 4 y = 0$

Factor $y$ out of $- 4 y$ .

$y \cdot y + y \cdot - 4 = 0$

Factor $y$ out of $y \cdot y + y \cdot - 4$ .

$y (y - 4) = 0$

Step 2

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$y = 0$

$y - 4 = 0$

Step 3

Set $y$ equal to $0$ .

$y = 0$

Step 4

Set $y - 4$ equal to $0$ and solve for $y$ .

Set $y - 4$ equal to $0$ .

$y - 4 = 0$

Add $4$ to both sides of the equation.

$y = 4$

Step 5

The final solution is all the values that make $y (y - 4) = 0$ true.

$y = 0, 4$