Solve Using the Square Root Property 9y^2-36y+37=0

$9 y^{2} - 36 y + 37 = 0$

Step 1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 2

Substitute the values $a = 9$ , $b = - 36$ , and $c = 37$ into the quadratic formula and solve for $y$ .

$\frac{36 \pm \sqrt{{(- 36)}^{2} - 4 \cdot (9 \cdot 37)}}{2 \cdot 9}$

Step 3

Simplify.

Simplify the numerator.

Raise $- 36$ to the power of $2$ .

$y = \frac{36 \pm \sqrt{1296 - 4 \cdot 9 \cdot 37}}{2 \cdot 9}$

Multiply $- 4 \cdot 9 \cdot 37$ .

Multiply $- 4$ by $9$ .

$y = \frac{36 \pm \sqrt{1296 - 36 \cdot 37}}{2 \cdot 9}$

Multiply $- 36$ by $37$ .

$y = \frac{36 \pm \sqrt{1296 - 1332}}{2 \cdot 9}$

Subtract $1332$ from $1296$ .

$y = \frac{36 \pm \sqrt{- 36}}{2 \cdot 9}$

Rewrite $- 36$ as $- 1 (36)$ .

$y = \frac{36 \pm \sqrt{- 1 \cdot 36}}{2 \cdot 9}$

Rewrite $\sqrt{- 1 (36)}$ as $\sqrt{- 1} \cdot \sqrt{36}$ .

$y = \frac{36 \pm \sqrt{- 1} \cdot \sqrt{36}}{2 \cdot 9}$

Rewrite $\sqrt{- 1}$ as $i$ .

$y = \frac{36 \pm i \cdot \sqrt{36}}{2 \cdot 9}$

Rewrite $36$ as $6^{2}$ .

$y = \frac{36 \pm i \cdot \sqrt{6^{2}}}{2 \cdot 9}$

Pull terms out from under the radical, assuming positive real numbers.

$y = \frac{36 \pm i \cdot 6}{2 \cdot 9}$

Move $6$ to the left of $i$ .

$y = \frac{36 \pm 6 i}{2 \cdot 9}$

Multiply $2$ by $9$ .

$y = \frac{36 \pm 6 i}{18}$

Simplify $\frac{36 \pm 6 i}{18}$ .

$y = \frac{6 \pm i}{3}$

Step 4

Simplify the expression to solve for the $+$ portion of the $\pm$ .

Simplify the numerator.

Raise $- 36$ to the power of $2$ .

$y = \frac{36 \pm \sqrt{1296 - 4 \cdot 9 \cdot 37}}{2 \cdot 9}$

Multiply $- 4 \cdot 9 \cdot 37$ .

Multiply $- 4$ by $9$ .

$y = \frac{36 \pm \sqrt{1296 - 36 \cdot 37}}{2 \cdot 9}$

Multiply $- 36$ by $37$ .

$y = \frac{36 \pm \sqrt{1296 - 1332}}{2 \cdot 9}$

Subtract $1332$ from $1296$ .

$y = \frac{36 \pm \sqrt{- 36}}{2 \cdot 9}$

Rewrite $- 36$ as $- 1 (36)$ .

$y = \frac{36 \pm \sqrt{- 1 \cdot 36}}{2 \cdot 9}$

Rewrite $\sqrt{- 1 (36)}$ as $\sqrt{- 1} \cdot \sqrt{36}$ .

$y = \frac{36 \pm \sqrt{- 1} \cdot \sqrt{36}}{2 \cdot 9}$

Rewrite $\sqrt{- 1}$ as $i$ .

$y = \frac{36 \pm i \cdot \sqrt{36}}{2 \cdot 9}$

Rewrite $36$ as $6^{2}$ .

$y = \frac{36 \pm i \cdot \sqrt{6^{2}}}{2 \cdot 9}$

Pull terms out from under the radical, assuming positive real numbers.

$y = \frac{36 \pm i \cdot 6}{2 \cdot 9}$

Move $6$ to the left of $i$ .

$y = \frac{36 \pm 6 i}{2 \cdot 9}$

Multiply $2$ by $9$ .

$y = \frac{36 \pm 6 i}{18}$

Simplify $\frac{36 \pm 6 i}{18}$ .

$y = \frac{6 \pm i}{3}$

Change the $\pm$ to $+$ .

$y = \frac{6 + i}{3}$

Split the fraction $\frac{6 + i}{3}$ into two fractions.

$y = \frac{6}{3} + \frac{i}{3}$

Divide $6$ by $3$ .

$y = 2 + \frac{i}{3}$

Step 5

Simplify the expression to solve for the $-$ portion of the $\pm$ .

Simplify the numerator.

Raise $- 36$ to the power of $2$ .

$y = \frac{36 \pm \sqrt{1296 - 4 \cdot 9 \cdot 37}}{2 \cdot 9}$

Multiply $- 4 \cdot 9 \cdot 37$ .

Multiply $- 4$ by $9$ .

$y = \frac{36 \pm \sqrt{1296 - 36 \cdot 37}}{2 \cdot 9}$

Multiply $- 36$ by $37$ .

$y = \frac{36 \pm \sqrt{1296 - 1332}}{2 \cdot 9}$

Subtract $1332$ from $1296$ .

$y = \frac{36 \pm \sqrt{- 36}}{2 \cdot 9}$

Rewrite $- 36$ as $- 1 (36)$ .

$y = \frac{36 \pm \sqrt{- 1 \cdot 36}}{2 \cdot 9}$

Rewrite $\sqrt{- 1 (36)}$ as $\sqrt{- 1} \cdot \sqrt{36}$ .

$y = \frac{36 \pm \sqrt{- 1} \cdot \sqrt{36}}{2 \cdot 9}$

Rewrite $\sqrt{- 1}$ as $i$ .

$y = \frac{36 \pm i \cdot \sqrt{36}}{2 \cdot 9}$

Rewrite $36$ as $6^{2}$ .

$y = \frac{36 \pm i \cdot \sqrt{6^{2}}}{2 \cdot 9}$

Pull terms out from under the radical, assuming positive real numbers.

$y = \frac{36 \pm i \cdot 6}{2 \cdot 9}$

Move $6$ to the left of $i$ .

$y = \frac{36 \pm 6 i}{2 \cdot 9}$

Multiply $2$ by $9$ .

$y = \frac{36 \pm 6 i}{18}$

Simplify $\frac{36 \pm 6 i}{18}$ .

$y = \frac{6 \pm i}{3}$

Change the $\pm$ to $-$ .

$y = \frac{6 - i}{3}$

Split the fraction $\frac{6 - i}{3}$ into two fractions.

$y = \frac{6}{3} + \frac{- i}{3}$

Simplify each term.

Divide $6$ by $3$ .

$y = 2 + \frac{- i}{3}$

Move the negative in front of the fraction.

$y = 2 - \frac{i}{3}$

Step 6

The final answer is the combination of both solutions.

$y = 2 + \frac{i}{3}, 2 - \frac{i}{3}$

Solve Using the Square Root Property 9y^2-36y+37=0

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