Solve for y (y-8)-(y+3)=9y

$(y - 8) - (y + 3) = 9 y$

Step 1

Simplify $y - 8 - (y + 3)$ .

Simplify each term.

Apply the distributive property.

$y - 8 - y - 1 \cdot 3 = 9 y$

Multiply $- 1$ by $3$ .

$y - 8 - y - 3 = 9 y$

Simplify by adding terms.

Combine the opposite terms in $y - 8 - y - 3$ .

Subtract $y$ from $y$ .

$0 - 8 - 3 = 9 y$

Subtract $8$ from $0$ .

$- 8 - 3 = 9 y$

Subtract $3$ from $- 8$ .

$- 11 = 9 y$

Step 2

Since $y$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$9 y = - 11$

Step 3

Divide each term in $9 y = - 11$ by $9$ and simplify.

Divide each term in $9 y = - 11$ by $9$ .

$\frac{9 y}{9} = \frac{- 11}{9}$

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{9 y}{9} = \frac{- 11}{9}$

Divide $y$ by $1$ .

$y = \frac{- 11}{9}$

Simplify the right side.

Move the negative in front of the fraction.

$y = - \frac{11}{9}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$y = - \frac{11}{9}$

Decimal Form:

$y = - 1.\overline{2}$

Mixed Number Form:

$y = - 1 \frac{2}{9}$