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Solve for y (y+4)(y-2)=0

$(y + 4) (y - 2) = 0$

Step 1

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$y + 4 = 0$

$y - 2 = 0$

Step 2

Set $y + 4$ equal to $0$ and solve for $y$ .

Set $y + 4$ equal to $0$ .

$y + 4 = 0$

Subtract $4$ from both sides of the equation.

$y = - 4$

$y = - 4$

Step 3

Set $y - 2$ equal to $0$ and solve for $y$ .

Set $y - 2$ equal to $0$ .

$y - 2 = 0$

Add $2$ to both sides of the equation.

$y = 2$

$y = 2$

Step 4

The final solution is all the values that make $(y + 4) (y - 2) = 0$ true.

$y = - 4, 2$

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