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Solve for y 3(y+2)-y=2(y-1)+5

$3 (y + 2) - y = 2 (y - 1) + 5$

Step 1

Simplify $3 (y + 2) - y$ .

Simplify each term.

Apply the distributive property.

$3 y + 3 \cdot 2 - y = 2 (y - 1) + 5$

Multiply $3$ by $2$ .

$3 y + 6 - y = 2 (y - 1) + 5$

$3 y + 6 - y = 2 (y - 1) + 5$

Subtract $y$ from $3 y$ .

$2 y + 6 = 2 (y - 1) + 5$

$2 y + 6 = 2 (y - 1) + 5$

Step 2

Simplify $2 (y - 1) + 5$ .

Simplify each term.

Apply the distributive property.

$2 y + 6 = 2 y + 2 \cdot - 1 + 5$

Multiply $2$ by $- 1$ .

$2 y + 6 = 2 y - 2 + 5$

$2 y + 6 = 2 y - 2 + 5$

Add $- 2$ and $5$ .

$2 y + 6 = 2 y + 3$

$2 y + 6 = 2 y + 3$

Step 3

Move all terms containing $y$ to the left side of the equation.

Subtract $2 y$ from both sides of the equation.

$2 y + 6 - 2 y = 3$

Combine the opposite terms in $2 y + 6 - 2 y$ .

Subtract $2 y$ from $2 y$ .

$0 + 6 = 3$

Add $0$ and $6$ .

$6 = 3$

$6 = 3$

$6 = 3$

Step 4

Since $6 \neq 3$ , there are no solutions.

No solution

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