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Solve for k 3(k-6)=15

$3 (k - 6) = 15$

Step 1

Divide each term in $3 (k - 6) = 15$ by $3$ and simplify.

Divide each term in $3 (k - 6) = 15$ by $3$ .

$\frac{3 (k - 6)}{3} = \frac{15}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 (k - 6)}{3} = \frac{15}{3}$

Divide $k - 6$ by $1$ .

$k - 6 = \frac{15}{3}$

$k - 6 = \frac{15}{3}$

$k - 6 = \frac{15}{3}$

Simplify the right side.

Divide $15$ by $3$ .

$k - 6 = 5$

$k - 6 = 5$

$k - 6 = 5$

Step 2

Move all terms not containing $k$ to the right side of the equation.

Add $6$ to both sides of the equation.

$k = 5 + 6$

Add $5$ and $6$ .

$k = 11$

$k = 11$

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