Solve for j (j+2)/(j-4)=(j+1)/(j-6)

$\frac{j + 2}{j - 4} = \frac{j + 1}{j - 6}$

Step 1

Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.

$(j + 2) (j - 6) = (j - 4) (j + 1)$

Step 2

Solve the equation for $j$ .

Simplify $(j + 2) (j - 6)$ .

Rewrite.

$0 + 0 + (j + 2) (j - 6) = (j - 4) (j + 1)$

Simplify by adding zeros.

$(j + 2) (j - 6) = (j - 4) (j + 1)$

Expand $(j + 2) (j - 6)$ using the FOIL Method.

Apply the distributive property.

$j (j - 6) + 2 (j - 6) = (j - 4) (j + 1)$

Apply the distributive property.

$j \cdot j + j \cdot - 6 + 2 (j - 6) = (j - 4) (j + 1)$

Apply the distributive property.

$j \cdot j + j \cdot - 6 + 2 j + 2 \cdot - 6 = (j - 4) (j + 1)$

Simplify and combine like terms.

Simplify each term.

Multiply $j$ by $j$ .

$j^{2} + j \cdot - 6 + 2 j + 2 \cdot - 6 = (j - 4) (j + 1)$

Move $- 6$ to the left of $j$ .

$j^{2} - 6 \cdot j + 2 j + 2 \cdot - 6 = (j - 4) (j + 1)$

Multiply $2$ by $- 6$ .

$j^{2} - 6 j + 2 j - 12 = (j - 4) (j + 1)$

Add $- 6 j$ and $2 j$ .

$j^{2} - 4 j - 12 = (j - 4) (j + 1)$

Simplify $(j - 4) (j + 1)$ .

Expand $(j - 4) (j + 1)$ using the FOIL Method.

Apply the distributive property.

$j^{2} - 4 j - 12 = j (j + 1) - 4 (j + 1)$

Apply the distributive property.

$j^{2} - 4 j - 12 = j \cdot j + j \cdot 1 - 4 (j + 1)$

Apply the distributive property.

$j^{2} - 4 j - 12 = j \cdot j + j \cdot 1 - 4 j - 4 \cdot 1$

Simplify and combine like terms.

Simplify each term.

Multiply $j$ by $j$ .

$j^{2} - 4 j - 12 = j^{2} + j \cdot 1 - 4 j - 4 \cdot 1$

Multiply $j$ by $1$ .

$j^{2} - 4 j - 12 = j^{2} + j - 4 j - 4 \cdot 1$

Multiply $- 4$ by $1$ .

$j^{2} - 4 j - 12 = j^{2} + j - 4 j - 4$

Subtract $4 j$ from $j$ .

$j^{2} - 4 j - 12 = j^{2} - 3 j - 4$

Move all terms containing $j$ to the left side of the equation.

Subtract $j^{2}$ from both sides of the equation.

$j^{2} - 4 j - 12 - j^{2} = - 3 j - 4$

Add $3 j$ to both sides of the equation.

$j^{2} - 4 j - 12 - j^{2} + 3 j = - 4$

Combine the opposite terms in $j^{2} - 4 j - 12 - j^{2} + 3 j$ .

Subtract $j^{2}$ from $j^{2}$ .

$- 4 j - 12 + 0 + 3 j = - 4$

Add $- 4 j - 12$ and $0$ .

$- 4 j - 12 + 3 j = - 4$

Add $- 4 j$ and $3 j$ .

$- j - 12 = - 4$

Move all terms not containing $j$ to the right side of the equation.

Add $12$ to both sides of the equation.

$- j = - 4 + 12$

Add $- 4$ and $12$ .

$- j = 8$

Divide each term in $- j = 8$ by $- 1$ and simplify.

Divide each term in $- j = 8$ by $- 1$ .

$\frac{- j}{- 1} = \frac{8}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{j}{1} = \frac{8}{- 1}$

Divide $j$ by $1$ .

$j = \frac{8}{- 1}$

Simplify the right side.

Divide $8$ by $- 1$ .

$j = - 8$

Solve for j (j+2)/(j-4)=(j+1)/(j-6)

Related Questions