Solve for g g(-2)=(1-(-2))/(1+(-2))

$g (- 2) = \frac{1 - (- 2)}{1 + (- 2)}$

Step 1

Simplify.

Multiply $- 1$ by $- 2$ .

$g (- 2) = \frac{1 + 2}{1 - 2}$

Add $1$ and $2$ .

$g (- 2) = \frac{3}{1 - 2}$

Subtract $2$ from $1$ .

$g (- 2) = \frac{3}{- 1}$

Divide $3$ by $- 1$ .

$g (- 2) = - 3$

Step 2

Divide each term in $g (- 2) = - 3$ by $- 2$ and simplify.

Divide each term in $g (- 2) = - 3$ by $- 2$ .

$\frac{g (- 2)}{- 2} = \frac{- 3}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{g \cdot - 2}{- 2} = \frac{- 3}{- 2}$

Divide $g$ by $1$ .

$g = \frac{- 3}{- 2}$

Simplify the right side.

Dividing two negative values results in a positive value.

$g = \frac{3}{2}$

Step 3

The result can be shown in multiple forms.

Exact Form:

$g = \frac{3}{2}$

Decimal Form:

$g = 1.5$

Mixed Number Form:

$g = 1 \frac{1}{2}$