Solve for d |d-4|+3=17

$| d - 4 | + 3 = 17$

Step 1

Move all terms not containing $| d - 4 |$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$| d - 4 | = 17 - 3$

Subtract $3$ from $17$ .

$| d - 4 | = 14$

Step 2

Remove the absolute value term. This creates a $\pm$ on the right side of the equation because $| x | = \pm x$ .

$d - 4 = \pm 14$

Step 3

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$d - 4 = 14$

Move all terms not containing $d$ to the right side of the equation.

Add $4$ to both sides of the equation.

$d = 14 + 4$

Add $14$ and $4$ .

$d = 18$

Next, use the negative value of the $\pm$ to find the second solution.

$d - 4 = - 14$

Move all terms not containing $d$ to the right side of the equation.

Add $4$ to both sides of the equation.

$d = - 14 + 4$

Add $- 14$ and $4$ .

$d = - 10$

The complete solution is the result of both the positive and negative portions of the solution.

$d = 18, - 10$