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Solve for d 41=12d-7

$41 = 12 d - 7$

Step 1

Rewrite the equation as $12 d - 7 = 41$ .

$12 d - 7 = 41$

Step 2

Move all terms not containing $d$ to the right side of the equation.

Add $7$ to both sides of the equation.

$12 d = 41 + 7$

Add $41$ and $7$ .

$12 d = 48$

$12 d = 48$

Step 3

Divide each term in $12 d = 48$ by $12$ and simplify.

Divide each term in $12 d = 48$ by $12$ .

$\frac{12 d}{12} = \frac{48}{12}$

Simplify the left side.

Cancel the common factor of $12$ .

Cancel the common factor.

$\frac{12 d}{12} = \frac{48}{12}$

Divide $d$ by $1$ .

$d = \frac{48}{12}$

$d = \frac{48}{12}$

$d = \frac{48}{12}$

Simplify the right side.

Divide $48$ by $12$ .

$d = 4$

$d = 4$

$d = 4$

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