Solve for c 3c-3(c-1)-4(c+3)=3*(1-c)-4c

$3 c - 3 \cdot (c - 1) - 4 \cdot (c + 3) = 3 \cdot (1 - c) - 4 c$

Step 1

Simplify $3 c - 3 \cdot (c - 1) - 4 \cdot (c + 3)$ .

Simplify each term.

Apply the distributive property.

$3 c - 3 c - 3 \cdot - 1 - 4 \cdot (c + 3) = 3 \cdot (1 - c) - 4 c$

Multiply $- 3$ by $- 1$ .

$3 c - 3 c + 3 - 4 \cdot (c + 3) = 3 \cdot (1 - c) - 4 c$

Apply the distributive property.

$3 c - 3 c + 3 - 4 c - 4 \cdot 3 = 3 \cdot (1 - c) - 4 c$

Multiply $- 4$ by $3$ .

$3 c - 3 c + 3 - 4 c - 12 = 3 \cdot (1 - c) - 4 c$

Simplify by adding terms.

Subtract $3 c$ from $3 c$ .

$0 + 3 - 4 c - 12 = 3 \cdot (1 - c) - 4 c$

Simplify by subtracting numbers.

Add $0$ and $3$ .

$3 - 4 c - 12 = 3 \cdot (1 - c) - 4 c$

Subtract $12$ from $3$ .

$- 4 c - 9 = 3 \cdot (1 - c) - 4 c$

Step 2

Simplify $3 \cdot (1 - c) - 4 c$ .

Simplify each term.

Apply the distributive property.

$- 4 c - 9 = 3 \cdot 1 + 3 (- c) - 4 c$

Multiply $3$ by $1$ .

$- 4 c - 9 = 3 + 3 (- c) - 4 c$

Multiply $- 1$ by $3$ .

$- 4 c - 9 = 3 - 3 c - 4 c$

Subtract $4 c$ from $- 3 c$ .

$- 4 c - 9 = 3 - 7 c$

Step 3

Move all terms containing $c$ to the left side of the equation.

Add $7 c$ to both sides of the equation.

$- 4 c - 9 + 7 c = 3$

Add $- 4 c$ and $7 c$ .

$3 c - 9 = 3$

Step 4

Move all terms not containing $c$ to the right side of the equation.

Add $9$ to both sides of the equation.

$3 c = 3 + 9$

Add $3$ and $9$ .

$3 c = 12$

Step 5

Divide each term in $3 c = 12$ by $3$ and simplify.

Divide each term in $3 c = 12$ by $3$ .

$\frac{3 c}{3} = \frac{12}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 c}{3} = \frac{12}{3}$

Divide $c$ by $1$ .

$c = \frac{12}{3}$

Simplify the right side.

Divide $12$ by $3$ .

$c = 4$

Solve for c 3c-3*(c-1)-4*(c+3)=3*(1-c)-4c

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Solve for c 3c-3(c-1)-4(c+3)=3*(1-c)-4c