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Solve for b (b-c+d)/9=a

$\frac{b - c + d}{9} = a$

Step 1

Multiply both sides by $9$ .

$\frac{b - c + d}{9} \cdot 9 = a \cdot 9$

Step 2

Simplify.

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{b - c + d}{9} \cdot 9 = a \cdot 9$

Rewrite the expression.

$b - c + d = a \cdot 9$

$b - c + d = a \cdot 9$

$b - c + d = a \cdot 9$

Simplify the right side.

Move $9$ to the left of $a$ .

$b - c + d = 9 a$

$b - c + d = 9 a$

$b - c + d = 9 a$

Step 3

Move all terms not containing $b$ to the right side of the equation.

Add $c$ to both sides of the equation.

$b + d = 9 a + c$

Subtract $d$ from both sides of the equation.

$b = 9 a + c - d$

$b = 9 a + c - d$

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