Solve for b b/4=(2b+3)/15

$\frac{b}{4} = \frac{2 b + 3}{15}$

Step 1

Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.

$b \cdot 15 = 4 (2 b + 3)$

Step 2

Solve the equation for $b$ .

Move $15$ to the left of $b$ .

$15 b = 4 (2 b + 3)$

Simplify $4 (2 b + 3)$ .

Apply the distributive property.

$15 b = 4 (2 b) + 4 \cdot 3$

Multiply.

Multiply $2$ by $4$ .

$15 b = 8 b + 4 \cdot 3$

Multiply $4$ by $3$ .

$15 b = 8 b + 12$

Move all terms containing $b$ to the left side of the equation.

Subtract $8 b$ from both sides of the equation.

$15 b - 8 b = 12$

Subtract $8 b$ from $15 b$ .

$7 b = 12$

Divide each term in $7 b = 12$ by $7$ and simplify.

Divide each term in $7 b = 12$ by $7$ .

$\frac{7 b}{7} = \frac{12}{7}$

Simplify the left side.

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7 b}{7} = \frac{12}{7}$

Divide $b$ by $1$ .

$b = \frac{12}{7}$

Step 3

The result can be shown in multiple forms.

Exact Form:

$b = \frac{12}{7}$

Decimal Form:

$b = 1.\overline{714285}$

Mixed Number Form:

$b = 1 \frac{5}{7}$

Solve for b b/4=(2b+3)/15

Related Questions