Solve for b -7+3b=4b-8

$- 7 + 3 b = 4 b - 8$

Step 1

Move all terms containing $b$ to the left side of the equation.

Subtract $4 b$ from both sides of the equation.

$- 7 + 3 b - 4 b = - 8$

Subtract $4 b$ from $3 b$ .

$- 7 - b = - 8$

Step 2

Move all terms not containing $b$ to the right side of the equation.

Add $7$ to both sides of the equation.

$- b = - 8 + 7$

Add $- 8$ and $7$ .

$- b = - 1$

Step 3

Divide each term in $- b = - 1$ by $- 1$ and simplify.

Divide each term in $- b = - 1$ by $- 1$ .

$\frac{- b}{- 1} = \frac{- 1}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{b}{1} = \frac{- 1}{- 1}$

Divide $b$ by $1$ .

$b = \frac{- 1}{- 1}$

Simplify the right side.

Divide $- 1$ by $- 1$ .

$b = 1$