Solve for b -4b+14=-11b+10

$- 4 b + 14 = - 11 b + 10$

Step 1

Move all terms containing $b$ to the left side of the equation.

Add $11 b$ to both sides of the equation.

$- 4 b + 14 + 11 b = 10$

Add $- 4 b$ and $11 b$ .

$7 b + 14 = 10$

Step 2

Move all terms not containing $b$ to the right side of the equation.

Subtract $14$ from both sides of the equation.

$7 b = 10 - 14$

Subtract $14$ from $10$ .

$7 b = - 4$

Step 3

Divide each term in $7 b = - 4$ by $7$ and simplify.

Divide each term in $7 b = - 4$ by $7$ .

$\frac{7 b}{7} = \frac{- 4}{7}$

Simplify the left side.

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7 b}{7} = \frac{- 4}{7}$

Divide $b$ by $1$ .

$b = \frac{- 4}{7}$

Simplify the right side.

Move the negative in front of the fraction.

$b = - \frac{4}{7}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$b = - \frac{4}{7}$

Decimal Form:

$b = - 0.\overline{571428}$