Solve for a (a^2+4)/(a^2-4)+a/(2-a)=2/(a+2)

$\frac{a^{2} + 4}{a^{2} - 4} + \frac{a}{2 - a} = \frac{2}{a + 2}$

Step 1

Factor each term.

Rewrite $4$ as $2^{2}$ .

$\frac{a^{2} + 4}{a^{2} - 2^{2}} + \frac{a}{2 - a} = \frac{2}{a + 2}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = a$ and $b = 2$ .

$\frac{a^{2} + 4}{(a + 2) (a - 2)} + \frac{a}{2 - a} = \frac{2}{a + 2}$

Step 2

Find the LCD of the terms in the equation.

Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.

$(a + 2) (a - 2), 2 - a, a + 2$

The LCM is the smallest positive number that all of the numbers divide into evenly.

1. List the prime factors of each number.

2. Multiply each factor the greatest number of times it occurs in either number.

The number $1$ is not a prime number because it only has one positive factor, which is itself.

Not prime

The LCM of $1, 1, 1$ is the result of multiplying all prime factors the greatest number of times they occur in either number.

$1$

The factor for $a + 2$ is $a + 2$ itself.

$(a + 2) = a + 2$

$(a + 2)$ occurs $1$ time.

The factor for $a - 2$ is $a - 2$ itself.

$(a - 2) = a - 2$

$(a - 2)$ occurs $1$ time.

The factor for $2 - a$ is $2 - a$ itself.

$(2 - a) = 2 - a$

$(2 - a)$ occurs $1$ time.

The factor for $a + 2$ is $a + 2$ itself.

$(a + 2) = a + 2$

$(a + 2)$ occurs $1$ time.

The LCM of $a + 2, a - 2, 2 - a, a + 2$ is the result of multiplying all factors the greatest number of times they occur in either term.

$(a + 2) (a - 2) (2 - a)$

Step 3

Multiply each term in $\frac{a^{2} + 4}{(a + 2) (a - 2)} + \frac{a}{2 - a} = \frac{2}{a + 2}$ by $(a + 2) (a - 2) (2 - a)$ to eliminate the fractions.

Multiply each term in $\frac{a^{2} + 4}{(a + 2) (a - 2)} + \frac{a}{2 - a} = \frac{2}{a + 2}$ by $(a + 2) (a - 2) (2 - a)$ .

$\frac{a^{2} + 4}{(a + 2) (a - 2)} ((a + 2) (a - 2) (2 - a)) + \frac{a}{2 - a} ((a + 2) (a - 2) (2 - a)) = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Simplify the left side.

Simplify each term.

Cancel the common factor of $(a + 2) (a - 2)$ .

Cancel the common factor.

$\frac{a^{2} + 4}{(a + 2) (a - 2)} ((a + 2) (a - 2) (2 - a)) + \frac{a}{2 - a} ((a + 2) (a - 2) (2 - a)) = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Rewrite the expression.

$(a^{2} + 4) (2 - a) + \frac{a}{2 - a} ((a + 2) (a - 2) (2 - a)) = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Expand $(a^{2} + 4) (2 - a)$ using the FOIL Method.

Apply the distributive property.

$a^{2} (2 - a) + 4 (2 - a) + \frac{a}{2 - a} ((a + 2) (a - 2) (2 - a)) = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Apply the distributive property.

$a^{2} \cdot 2 + a^{2} (- a) + 4 (2 - a) + \frac{a}{2 - a} ((a + 2) (a - 2) (2 - a)) = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Apply the distributive property.

$a^{2} \cdot 2 + a^{2} (- a) + 4 \cdot 2 + 4 (- a) + \frac{a}{2 - a} ((a + 2) (a - 2) (2 - a)) = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Simplify each term.

Move $2$ to the left of $a^{2}$ .

$2 \cdot a^{2} + a^{2} (- a) + 4 \cdot 2 + 4 (- a) + \frac{a}{2 - a} ((a + 2) (a - 2) (2 - a)) = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Rewrite using the commutative property of multiplication.

$2 a^{2} - a^{2} a + 4 \cdot 2 + 4 (- a) + \frac{a}{2 - a} ((a + 2) (a - 2) (2 - a)) = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Multiply $a^{2}$ by $a$ by adding the exponents.

Move $a$ .

$2 a^{2} - (a \cdot a^{2}) + 4 \cdot 2 + 4 (- a) + \frac{a}{2 - a} ((a + 2) (a - 2) (2 - a)) = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Multiply $a$ by $a^{2}$ .

Raise $a$ to the power of $1$ .

$2 a^{2} - (a^{1} a^{2}) + 4 \cdot 2 + 4 (- a) + \frac{a}{2 - a} ((a + 2) (a - 2) (2 - a)) = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$2 a^{2} - a^{1 + 2} + 4 \cdot 2 + 4 (- a) + \frac{a}{2 - a} ((a + 2) (a - 2) (2 - a)) = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Add $1$ and $2$ .

$2 a^{2} - a^{3} + 4 \cdot 2 + 4 (- a) + \frac{a}{2 - a} ((a + 2) (a - 2) (2 - a)) = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Multiply $4$ by $2$ .

$2 a^{2} - a^{3} + 8 + 4 (- a) + \frac{a}{2 - a} ((a + 2) (a - 2) (2 - a)) = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Multiply $- 1$ by $4$ .

$2 a^{2} - a^{3} + 8 - 4 a + \frac{a}{2 - a} ((a + 2) (a - 2) (2 - a)) = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Cancel the common factor of $2 - a$ .

Factor $2 - a$ out of $(a + 2) (a - 2) (2 - a)$ .

$2 a^{2} - a^{3} + 8 - 4 a + \frac{a}{2 - a} ((2 - a) ((a + 2) (a - 2))) = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Cancel the common factor.

$2 a^{2} - a^{3} + 8 - 4 a + \frac{a}{2 - a} ((2 - a) ((a + 2) (a - 2))) = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Rewrite the expression.

$2 a^{2} - a^{3} + 8 - 4 a + a ((a + 2) (a - 2)) = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Expand $(a + 2) (a - 2)$ using the FOIL Method.

Apply the distributive property.

$2 a^{2} - a^{3} + 8 - 4 a + a (a (a - 2) + 2 (a - 2)) = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Apply the distributive property.

$2 a^{2} - a^{3} + 8 - 4 a + a (a \cdot a + a \cdot - 2 + 2 (a - 2)) = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Apply the distributive property.

$2 a^{2} - a^{3} + 8 - 4 a + a (a \cdot a + a \cdot - 2 + 2 a + 2 \cdot - 2) = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Combine the opposite terms in $a \cdot a + a \cdot - 2 + 2 a + 2 \cdot - 2$ .

Reorder the factors in the terms $a \cdot - 2$ and $2 a$ .

$2 a^{2} - a^{3} + 8 - 4 a + a (a \cdot a - 2 a + 2 a + 2 \cdot - 2) = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Add $- 2 a$ and $2 a$ .

$2 a^{2} - a^{3} + 8 - 4 a + a (a \cdot a + 0 + 2 \cdot - 2) = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Add $a \cdot a$ and $0$ .

$2 a^{2} - a^{3} + 8 - 4 a + a (a \cdot a + 2 \cdot - 2) = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Simplify each term.

Multiply $a$ by $a$ .

$2 a^{2} - a^{3} + 8 - 4 a + a (a^{2} + 2 \cdot - 2) = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Multiply $2$ by $- 2$ .

$2 a^{2} - a^{3} + 8 - 4 a + a (a^{2} - 4) = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Apply the distributive property.

$2 a^{2} - a^{3} + 8 - 4 a + a \cdot a^{2} + a \cdot - 4 = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Multiply $a$ by $a^{2}$ by adding the exponents.

Multiply $a$ by $a^{2}$ .

Raise $a$ to the power of $1$ .

$2 a^{2} - a^{3} + 8 - 4 a + a^{1} a^{2} + a \cdot - 4 = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$2 a^{2} - a^{3} + 8 - 4 a + a^{1 + 2} + a \cdot - 4 = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Add $1$ and $2$ .

$2 a^{2} - a^{3} + 8 - 4 a + a^{3} + a \cdot - 4 = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Move $- 4$ to the left of $a$ .

$2 a^{2} - a^{3} + 8 - 4 a + a^{3} - 4 a = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Simplify by adding terms.

Combine the opposite terms in $2 a^{2} - a^{3} + 8 - 4 a + a^{3} - 4 a$ .

Add $- a^{3}$ and $a^{3}$ .

$2 a^{2} + 8 - 4 a + 0 - 4 a = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Add $2 a^{2} + 8 - 4 a$ and $0$ .

$2 a^{2} + 8 - 4 a - 4 a = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Subtract $4 a$ from $- 4 a$ .

$2 a^{2} + 8 - 8 a = \frac{2}{a + 2} ((a + 2) (a - 2) (2 - a))$

Simplify the right side.

Cancel the common factor of $a + 2$ .

Factor $a + 2$ out of $(a + 2) (a - 2) (2 - a)$ .

$2 a^{2} + 8 - 8 a = \frac{2}{a + 2} ((a + 2) ((a - 2) (2 - a)))$

Cancel the common factor.

$2 a^{2} + 8 - 8 a = \frac{2}{a + 2} ((a + 2) ((a - 2) (2 - a)))$

Rewrite the expression.

$2 a^{2} + 8 - 8 a = 2 ((a - 2) (2 - a))$

Factor $- 1$ out of $a$ .

$2 a^{2} + 8 - 8 a = 2 ((- 1 (- a) - 2) (2 - a))$

Rewrite $- 2$ as $- 1 (2)$ .

$2 a^{2} + 8 - 8 a = 2 ((- 1 (- a) - 1 (2)) (2 - a))$

Factor $- 1$ out of $- 1 (- a) - 1 (2)$ .

$2 a^{2} + 8 - 8 a = 2 (- 1 (- a + 2) (2 - a))$

Reorder terms.

$2 a^{2} + 8 - 8 a = 2 (- 1 (- a + 2) (- a + 2))$

Raise $- a + 2$ to the power of $1$ .

$2 a^{2} + 8 - 8 a = 2 (- 1 ({(- a + 2)}^{1} (- a + 2)))$

Raise $- a + 2$ to the power of $1$ .

$2 a^{2} + 8 - 8 a = 2 (- 1 ({(- a + 2)}^{1} {(- a + 2)}^{1}))$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$2 a^{2} + 8 - 8 a = 2 (- 1 {(- a + 2)}^{1 + 1})$

Add $1$ and $1$ .

$2 a^{2} + 8 - 8 a = 2 (- 1 {(- a + 2)}^{2})$

Multiply $- 1$ by $2$ .

$2 a^{2} + 8 - 8 a = - 2 {(- a + 2)}^{2}$

Step 4

Solve the equation.

Simplify $- 2 {(- a + 2)}^{2}$ .

Rewrite.

$2 a^{2} + 8 - 8 a = 0 + 0 - 2 {(- a + 2)}^{2}$

Rewrite ${(- a + 2)}^{2}$ as $(- a + 2) (- a + 2)$ .

$2 a^{2} + 8 - 8 a = - 2 ((- a + 2) (- a + 2))$

Expand $(- a + 2) (- a + 2)$ using the FOIL Method.

Apply the distributive property.

$2 a^{2} + 8 - 8 a = - 2 (- a (- a + 2) + 2 (- a + 2))$

Apply the distributive property.

$2 a^{2} + 8 - 8 a = - 2 (- a (- a) - a \cdot 2 + 2 (- a + 2))$

Apply the distributive property.

$2 a^{2} + 8 - 8 a = - 2 (- a (- a) - a \cdot 2 + 2 (- a) + 2 \cdot 2)$

Simplify and combine like terms.

Simplify each term.

Rewrite using the commutative property of multiplication.

$2 a^{2} + 8 - 8 a = - 2 (- 1 \cdot - 1 a \cdot a - a \cdot 2 + 2 (- a) + 2 \cdot 2)$

Multiply $a$ by $a$ by adding the exponents.

Move $a$ .

$2 a^{2} + 8 - 8 a = - 2 (- 1 \cdot - 1 (a \cdot a) - a \cdot 2 + 2 (- a) + 2 \cdot 2)$

Multiply $a$ by $a$ .

$2 a^{2} + 8 - 8 a = - 2 (- 1 \cdot - 1 a^{2} - a \cdot 2 + 2 (- a) + 2 \cdot 2)$

Multiply $- 1$ by $- 1$ .

$2 a^{2} + 8 - 8 a = - 2 (1 a^{2} - a \cdot 2 + 2 (- a) + 2 \cdot 2)$

Multiply $a^{2}$ by $1$ .

$2 a^{2} + 8 - 8 a = - 2 (a^{2} - a \cdot 2 + 2 (- a) + 2 \cdot 2)$

Multiply $2$ by $- 1$ .

$2 a^{2} + 8 - 8 a = - 2 (a^{2} - 2 a + 2 (- a) + 2 \cdot 2)$

Multiply $- 1$ by $2$ .

$2 a^{2} + 8 - 8 a = - 2 (a^{2} - 2 a - 2 a + 2 \cdot 2)$

Multiply $2$ by $2$ .

$2 a^{2} + 8 - 8 a = - 2 (a^{2} - 2 a - 2 a + 4)$

Subtract $2 a$ from $- 2 a$ .

$2 a^{2} + 8 - 8 a = - 2 (a^{2} - 4 a + 4)$

Apply the distributive property.

$2 a^{2} + 8 - 8 a = - 2 a^{2} - 2 (- 4 a) - 2 \cdot 4$

Simplify.

Multiply $- 4$ by $- 2$ .

$2 a^{2} + 8 - 8 a = - 2 a^{2} + 8 a - 2 \cdot 4$

Multiply $- 2$ by $4$ .

$2 a^{2} + 8 - 8 a = - 2 a^{2} + 8 a - 8$

Move all terms containing $a$ to the left side of the equation.

Add $2 a^{2}$ to both sides of the equation.

$2 a^{2} + 8 - 8 a + 2 a^{2} = 8 a - 8$

Subtract $8 a$ from both sides of the equation.

$2 a^{2} + 8 - 8 a + 2 a^{2} - 8 a = - 8$

Add $2 a^{2}$ and $2 a^{2}$ .

$4 a^{2} + 8 - 8 a - 8 a = - 8$

Subtract $8 a$ from $- 8 a$ .

$4 a^{2} + 8 - 16 a = - 8$

Add $8$ to both sides of the equation.

$4 a^{2} + 8 - 16 a + 8 = 0$

Add $8$ and $8$ .

$4 a^{2} - 16 a + 16 = 0$

Factor the left side of the equation.

Factor $4$ out of $4 a^{2} - 16 a + 16$ .

Factor $4$ out of $4 a^{2}$ .

$4 (a^{2}) - 16 a + 16 = 0$

Factor $4$ out of $- 16 a$ .

$4 (a^{2}) + 4 (- 4 a) + 16 = 0$

Factor $4$ out of $16$ .

$4 a^{2} + 4 (- 4 a) + 4 \cdot 4 = 0$

Factor $4$ out of $4 a^{2} + 4 (- 4 a)$ .

$4 (a^{2} - 4 a) + 4 \cdot 4 = 0$

Factor $4$ out of $4 (a^{2} - 4 a) + 4 \cdot 4$ .

$4 (a^{2} - 4 a + 4) = 0$

Factor using the perfect square rule.

Rewrite $4$ as $2^{2}$ .

$4 (a^{2} - 4 a + 2^{2}) = 0$

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

$4 a = 2 \cdot a \cdot 2$

Rewrite the polynomial.

$4 (a^{2} - 2 \cdot a \cdot 2 + 2^{2}) = 0$

Factor using the perfect square trinomial rule $a^{2} - 2 a b + b^{2} = {(a - b)}^{2}$ , where $a = a$ and $b = 2$ .

$4 {(a - 2)}^{2} = 0$

Divide each term in $4 {(a - 2)}^{2} = 0$ by $4$ and simplify.

Divide each term in $4 {(a - 2)}^{2} = 0$ by $4$ .

$\frac{4 {(a - 2)}^{2}}{4} = \frac{0}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 {(a - 2)}^{2}}{4} = \frac{0}{4}$

Divide ${(a - 2)}^{2}$ by $1$ .

${(a - 2)}^{2} = \frac{0}{4}$

Simplify the right side.

Divide $0$ by $4$ .

${(a - 2)}^{2} = 0$

Set the $a - 2$ equal to $0$ .

$a - 2 = 0$

Add $2$ to both sides of the equation.

$a = 2$

Step 5

Exclude the solutions that do not make $\frac{a^{2} + 4}{a^{2} - 4} + \frac{a}{2 - a} = \frac{2}{a + 2}$ true.

$No solution$

Solve for a (a^2+4)/(a^2-4)+a/(2-a)=2/(a+2)

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