Solve for A A=1/3*(h(a+4b+c))

$A = \frac{1}{3} \cdot (h (a + 4 b + c))$

Step 1

Remove parentheses.

$A = \frac{1}{3} \cdot (h (a + 4 b + c))$

Step 2

Simplify $\frac{1}{3} \cdot (h (a + 4 b + c))$ .

Apply the distributive property.

$A = \frac{1}{3} \cdot (h a + h (4 b) + h c)$

Rewrite using the commutative property of multiplication.

$A = \frac{1}{3} \cdot (h a + 4 h b + h c)$

Apply the distributive property.

$A = \frac{1}{3} (h a) + \frac{1}{3} (4 h b) + \frac{1}{3} (h c)$

Simplify.

Multiply $\frac{1}{3} (h a)$ .

Combine $h$ and $\frac{1}{3}$ .

$A = \frac{h}{3} a + \frac{1}{3} (4 h b) + \frac{1}{3} (h c)$

Combine $\frac{h}{3}$ and $a$ .

$A = \frac{h a}{3} + \frac{1}{3} (4 h b) + \frac{1}{3} (h c)$

Multiply $\frac{1}{3} (4 h b)$ .

Combine $4$ and $\frac{1}{3}$ .

$A = \frac{h a}{3} + \frac{4}{3} (h b) + \frac{1}{3} (h c)$

Combine $h$ and $\frac{4}{3}$ .

$A = \frac{h a}{3} + \frac{h \cdot 4}{3} b + \frac{1}{3} (h c)$

Combine $\frac{h \cdot 4}{3}$ and $b$ .

$A = \frac{h a}{3} + \frac{h \cdot 4 b}{3} + \frac{1}{3} (h c)$

Multiply $\frac{1}{3} (h c)$ .

Combine $h$ and $\frac{1}{3}$ .

$A = \frac{h a}{3} + \frac{h \cdot 4 b}{3} + \frac{h}{3} c$

Combine $\frac{h}{3}$ and $c$ .

$A = \frac{h a}{3} + \frac{h \cdot 4 b}{3} + \frac{h c}{3}$

Move $4$ to the left of $h$ .

$A = \frac{h a}{3} + \frac{4 h b}{3} + \frac{h c}{3}$

Simplify the expression.

Reorder $h$ and $a$ .

$A = \frac{a h}{3} + \frac{4 h b}{3} + \frac{h c}{3}$

Move $h$ .

$A = \frac{a h}{3} + \frac{4 b h}{3} + \frac{h c}{3}$

Reorder $h$ and $c$ .

$A = \frac{a h}{3} + \frac{4 b h}{3} + \frac{c h}{3}$