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Simplify (-2d^2+6d+1)-2(4d^2-3d+1)

$(- 2 d^{2} + 6 d + 1) - 2 (4 d^{2} - 3 d + 1)$

Step 1

Simplify each term.

Apply the distributive property.

$- 2 d^{2} + 6 d + 1 - 2 (4 d^{2}) - 2 (- 3 d) - 2 \cdot 1$

Simplify.

Multiply $4$ by $- 2$ .

$- 2 d^{2} + 6 d + 1 - 8 d^{2} - 2 (- 3 d) - 2 \cdot 1$

Multiply $- 3$ by $- 2$ .

$- 2 d^{2} + 6 d + 1 - 8 d^{2} + 6 d - 2 \cdot 1$

Multiply $- 2$ by $1$ .

$- 2 d^{2} + 6 d + 1 - 8 d^{2} + 6 d - 2$

$- 2 d^{2} + 6 d + 1 - 8 d^{2} + 6 d - 2$

$- 2 d^{2} + 6 d + 1 - 8 d^{2} + 6 d - 2$

Step 2

Simplify by adding terms.

Subtract $8 d^{2}$ from $- 2 d^{2}$ .

$- 10 d^{2} + 6 d + 1 + 6 d - 2$

Add $6 d$ and $6 d$ .

$- 10 d^{2} + 12 d + 1 - 2$

Subtract $2$ from $1$ .

$- 10 d^{2} + 12 d - 1$

$- 10 d^{2} + 12 d - 1$

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