Processing math: 100%

Simplify |(-2)^2+6(3-15)|+(-9) square root of 81*16

$| {(- 2)}^{2} + 6 (3 - 15) | + (- 9) \sqrt{81 \cdot 16}$

Step 1

Simplify each term.

Raise

$- 2$ to the power of

$2$ .

$| 4 + 6 (3 - 15) | + (- 9) \sqrt{81 \cdot 16}$

Subtract

$15$ from

$3$ .

$| 4 + 6 \cdot - 12 | + (- 9) \sqrt{81 \cdot 16}$

Multiply

$6$ by

$- 12$ .

$| 4 - 72 | + (- 9) \sqrt{81 \cdot 16}$

Subtract

$72$ from

$4$ .

$| - 68 | + (- 9) \sqrt{81 \cdot 16}$

The absolute value is the distance between a number and zero. The distance between

$- 68$ and

$0$ is

$68$ .

$68 + (- 9) \sqrt{81 \cdot 16}$

Multiply

$81$ by

$16$ .

$68 - 9 \sqrt{1296}$

Rewrite

$1296$ as

$36^{2}$ .

$68 - 9 \sqrt{36^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$68 - 9 \cdot 36$

Multiply

$- 9$ by

$36$ .

$68 - 324$

Step 2

Subtract

$324$ from

$68$ .

$- 256$