Simplify (1+2i)^33+(11+2i)^11+(1+i)^4+(1-i)^4

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} + {(1 + i)}^{4} + {(1 - i)}^{4}$

Step 1

Simplify each term.

Use the Binomial Theorem.

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} + 1^{4} + 4 \cdot 1^{3} i + 6 \cdot 1^{2} i^{2} + 4 \cdot 1 i^{3} + i^{4} + {(1 - i)}^{4}$

Simplify each term.

One to any power is one.

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} + 1 + 4 \cdot 1^{3} i + 6 \cdot 1^{2} i^{2} + 4 \cdot 1 i^{3} + i^{4} + {(1 - i)}^{4}$

One to any power is one.

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} + 1 + 4 \cdot 1 i + 6 \cdot 1^{2} i^{2} + 4 \cdot 1 i^{3} + i^{4} + {(1 - i)}^{4}$

Multiply

$4$ by

$1$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} + 1 + 4 i + 6 \cdot 1^{2} i^{2} + 4 \cdot 1 i^{3} + i^{4} + {(1 - i)}^{4}$

One to any power is one.

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} + 1 + 4 i + 6 \cdot 1 i^{2} + 4 \cdot 1 i^{3} + i^{4} + {(1 - i)}^{4}$

Multiply

$6$ by

$1$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} + 1 + 4 i + 6 i^{2} + 4 \cdot 1 i^{3} + i^{4} + {(1 - i)}^{4}$

Rewrite

$i^{2}$ as

$- 1$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} + 1 + 4 i + 6 \cdot - 1 + 4 \cdot 1 i^{3} + i^{4} + {(1 - i)}^{4}$

Multiply

$6$ by

$- 1$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} + 1 + 4 i - 6 + 4 \cdot 1 i^{3} + i^{4} + {(1 - i)}^{4}$

Multiply

$4$ by

$1$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} + 1 + 4 i - 6 + 4 i^{3} + i^{4} + {(1 - i)}^{4}$

Factor out

$i^{2}$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} + 1 + 4 i - 6 + 4 (i^{2} \cdot i) + i^{4} + {(1 - i)}^{4}$

Rewrite

$i^{2}$ as

$- 1$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} + 1 + 4 i - 6 + 4 (- 1 \cdot i) + i^{4} + {(1 - i)}^{4}$

Rewrite

$- 1 i$ as

$- i$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} + 1 + 4 i - 6 + 4 (- i) + i^{4} + {(1 - i)}^{4}$

Multiply

$- 1$ by

$4$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} + 1 + 4 i - 6 - 4 i + i^{4} + {(1 - i)}^{4}$

Rewrite

$i^{4}$ as

$1$ .

Rewrite

$i^{4}$ as

${(i^{2})}^{2}$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} + 1 + 4 i - 6 - 4 i + {(i^{2})}^{2} + {(1 - i)}^{4}$

Rewrite

$i^{2}$ as

$- 1$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} + 1 + 4 i - 6 - 4 i + {(- 1)}^{2} + {(1 - i)}^{4}$

Raise

$- 1$ to the power of

$2$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} + 1 + 4 i - 6 - 4 i + 1 + {(1 - i)}^{4}$

Subtract

$6$ from

$1$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 5 + 4 i - 4 i + 1 + {(1 - i)}^{4}$

Add

$- 5$ and

$1$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 4 i - 4 i + {(1 - i)}^{4}$

Subtract

$4 i$ from

$4 i$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 0 + {(1 - i)}^{4}$

Add

$- 4$ and

$0$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + {(1 - i)}^{4}$

Use the Binomial Theorem.

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 1^{4} + 4 \cdot 1^{3} (- i) + 6 \cdot 1^{2} {(- i)}^{2} + 4 \cdot 1 {(- i)}^{3} + {(- i)}^{4}$

Simplify each term.

One to any power is one.

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 1 + 4 \cdot 1^{3} (- i) + 6 \cdot 1^{2} {(- i)}^{2} + 4 \cdot 1 {(- i)}^{3} + {(- i)}^{4}$

One to any power is one.

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 1 + 4 \cdot 1 (- i) + 6 \cdot 1^{2} {(- i)}^{2} + 4 \cdot 1 {(- i)}^{3} + {(- i)}^{4}$

Multiply

$4$ by

$1$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 1 + 4 (- i) + 6 \cdot 1^{2} {(- i)}^{2} + 4 \cdot 1 {(- i)}^{3} + {(- i)}^{4}$

Multiply

$- 1$ by

$4$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 1 - 4 i + 6 \cdot 1^{2} {(- i)}^{2} + 4 \cdot 1 {(- i)}^{3} + {(- i)}^{4}$

One to any power is one.

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 1 - 4 i + 6 \cdot 1 {(- i)}^{2} + 4 \cdot 1 {(- i)}^{3} + {(- i)}^{4}$

Multiply

$6$ by

$1$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 1 - 4 i + 6 {(- i)}^{2} + 4 \cdot 1 {(- i)}^{3} + {(- i)}^{4}$

Apply the product rule to

$- i$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 1 - 4 i + 6 ({(- 1)}^{2} i^{2}) + 4 \cdot 1 {(- i)}^{3} + {(- i)}^{4}$

Raise

$- 1$ to the power of

$2$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 1 - 4 i + 6 (1 i^{2}) + 4 \cdot 1 {(- i)}^{3} + {(- i)}^{4}$

Multiply

$i^{2}$ by

$1$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 1 - 4 i + 6 i^{2} + 4 \cdot 1 {(- i)}^{3} + {(- i)}^{4}$

Rewrite

$i^{2}$ as

$- 1$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 1 - 4 i + 6 \cdot - 1 + 4 \cdot 1 {(- i)}^{3} + {(- i)}^{4}$

Multiply

$6$ by

$- 1$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 1 - 4 i - 6 + 4 \cdot 1 {(- i)}^{3} + {(- i)}^{4}$

Multiply

$4$ by

$1$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 1 - 4 i - 6 + 4 {(- i)}^{3} + {(- i)}^{4}$

Apply the product rule to

$- i$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 1 - 4 i - 6 + 4 ({(- 1)}^{3} i^{3}) + {(- i)}^{4}$

Raise

$- 1$ to the power of

$3$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 1 - 4 i - 6 + 4 (- i^{3}) + {(- i)}^{4}$

Factor out

$i^{2}$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 1 - 4 i - 6 + 4 (- (i^{2} \cdot i)) + {(- i)}^{4}$

Rewrite

$i^{2}$ as

$- 1$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 1 - 4 i - 6 + 4 (- (- 1 \cdot i)) + {(- i)}^{4}$

Rewrite

$- 1 i$ as

$- i$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 1 - 4 i - 6 + 4 (- - i) + {(- i)}^{4}$

Multiply

$- 1$ by

$- 1$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 1 - 4 i - 6 + 4 (1 i) + {(- i)}^{4}$

Multiply

$i$ by

$1$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 1 - 4 i - 6 + 4 i + {(- i)}^{4}$

Apply the product rule to

$- i$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 1 - 4 i - 6 + 4 i + {(- 1)}^{4} i^{4}$

Raise

$- 1$ to the power of

$4$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 1 - 4 i - 6 + 4 i + 1 i^{4}$

Multiply

$i^{4}$ by

$1$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 1 - 4 i - 6 + 4 i + i^{4}$

Rewrite

$i^{4}$ as

$1$ .

Rewrite

$i^{4}$ as

${(i^{2})}^{2}$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 1 - 4 i - 6 + 4 i + {(i^{2})}^{2}$

Rewrite

$i^{2}$ as

$- 1$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 1 - 4 i - 6 + 4 i + {(- 1)}^{2}$

Raise

$- 1$ to the power of

$2$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 + 1 - 4 i - 6 + 4 i + 1$

Subtract

$6$ from

$1$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 - 5 - 4 i + 4 i + 1$

Add

$- 5$ and

$1$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 - 4 - 4 i + 4 i$

Add

$- 4 i$ and

$4 i$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 - 4 + 0$

Add

$- 4$ and

$0$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 4 - 4$

Step 2

Simplify the expression.

Subtract

$4$ from

$- 4$ .

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11} - 8$

Reorder

${(1 + 2 i)}^{33} + {(11 + 2 i)}^{11}$ and

$- 8$ .

$- 8 + {(1 + 2 i)}^{33} + {(11 + 2 i)}^{11}$

Simplify (1+2i)^33+(11+2i)^11+(1+i)^4+(1-i)^4

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