Find the Midpoint (-2,8) , (1,6)

$(- 2, 8)$ , $(1, 6)$

Step 1

Use the midpoint formula to find the midpoint of the line segment.

$(\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})$

Step 2

Substitute in the values for $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ .

$(\frac{- 2 + 1}{2}, \frac{8 + 6}{2})$

Step 3

Add $- 2$ and $1$ .

$(\frac{- 1}{2}, \frac{8 + 6}{2})$

Step 4

Move the negative in front of the fraction.

$(- \frac{1}{2}, \frac{8 + 6}{2})$

Step 5

Cancel the common factor of $8 + 6$ and $2$ .

Factor $2$ out of $8$ .

$(- \frac{1}{2}, \frac{2 \cdot 4 + 6}{2})$

Factor $2$ out of $6$ .

$(- \frac{1}{2}, \frac{2 \cdot 4 + 2 \cdot 3}{2})$

Factor $2$ out of $2 \cdot 4 + 2 \cdot 3$ .

$(- \frac{1}{2}, \frac{2 \cdot (4 + 3)}{2})$

Cancel the common factors.

Factor $2$ out of $2$ .

$(- \frac{1}{2}, \frac{2 \cdot (4 + 3)}{2 (1)})$

Cancel the common factor.

$(- \frac{1}{2}, \frac{2 \cdot (4 + 3)}{2 \cdot 1})$

Rewrite the expression.

$(- \frac{1}{2}, \frac{4 + 3}{1})$

Divide $4 + 3$ by $1$ .

$(- \frac{1}{2}, 4 + 3)$

Step 6

Add $4$ and $3$ .

$(- \frac{1}{2}, 7)$

Step 7