Find the Median 11 , 13 , 12 , 12 , 12 , 13 , 9 , 14

$11$ , $13$ , $12$ , $12$ , $12$ , $13$ , $9$ , $14$

Step 1

Arrange the terms in ascending order.

$9, 11, 12, 12, 12, 13, 13, 14$

Step 2

The median is the middle term in the arranged data set. In the case of an even number of terms, the median is the average of the two middle terms.

$\frac{12 + 12}{2}$

Step 3

Remove parentheses.

$\frac{12 + 12}{2}$

Step 4

Cancel the common factor of $12 + 12$ and $2$ .

Factor $2$ out of $12$ .

$\frac{2 \cdot 6 + 12}{2}$

Factor $2$ out of $12$ .

$\frac{2 \cdot 6 + 2 \cdot 6}{2}$

Factor $2$ out of $2 \cdot 6 + 2 \cdot 6$ .

$\frac{2 \cdot (6 + 6)}{2}$

Cancel the common factors.

Factor $2$ out of $2$ .

$\frac{2 \cdot (6 + 6)}{2 (1)}$

Cancel the common factor.

$\frac{2 \cdot (6 + 6)}{2 \cdot 1}$

Rewrite the expression.

$\frac{6 + 6}{1}$

Divide $6 + 6$ by $1$ .

$6 + 6$

Step 5

Add $6$ and $6$ .

$12$

Step 6

Convert the median $12$ to decimal.

$12$