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Find the Mean 7(9.9)^2+13-9 , 0.9

$7 {(9.9)}^{2} + 13 - 9$ ,

$0.9$

Step 1

Simplify each term.

Raise

$9.9$ to the power of

$2$ .

$7 \cdot 98.01 + 13 - 9, 0.9$

Multiply

$7$ by

$98.01$ .

$686.07 + 13 - 9, 0.9$

Step 2

Simplify by adding and subtracting.

Add

$686.07$ and

$13$ .

$699.07 - 9, 0.9$

Subtract

$9$ from

$699.07$ .

$690.07, 0.9$

Step 3

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{690.07 + 0.9}{2}$

Step 4

Add

$690.07$ and

$0.9$ .

$\frac{690.97}{2}$

Step 5

Divide

$690.97$ by

$2$ .

$345.485$

Step 6

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

$345.49$

Find the Mean 7(9.9)^2+13-9 , 0.9

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