Find the Mean 68 square root of 24 , 412

$68 \sqrt{24}$ ,

$412$

Step 1

Rewrite

$24$ as

$2^{2} \cdot 6$ .

Factor

$4$ out of

$24$ .

$68 \sqrt{4 (6)}, 412$

Rewrite

$4$ as

$2^{2}$ .

$68 \sqrt{2^{2} \cdot 6}, 412$

Step 2

Pull terms out from under the radical.

$68 (2 \sqrt{6}), 412$

Step 3

Multiply

$2$ by

$68$ .

$136 \sqrt{6}, 412$

Step 4

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{136 \sqrt{6} + 412}{2}$

Step 5

Cancel the common factor of

$136 \sqrt{6} + 412$ and

$2$ .

Factor

$2$ out of

$136 \sqrt{6}$ .

$\frac{2 (68 \sqrt{6}) + 412}{2}$

Factor

$2$ out of

$412$ .

$\frac{2 (68 \sqrt{6}) + 2 \cdot 206}{2}$

Factor

$2$ out of

$2 (68 \sqrt{6}) + 2 (206)$ .

$\frac{2 (68 \sqrt{6} + 206)}{2}$

Cancel the common factors.

Factor

$2$ out of

$2$ .

$\frac{2 (68 \sqrt{6} + 206)}{2 (1)}$

Cancel the common factor.

$\frac{2 (68 \sqrt{6} + 206)}{2 \cdot 1}$

Rewrite the expression.

$\frac{68 \sqrt{6} + 206}{1}$

Divide

$68 \sqrt{6} + 206$ by

$1$ .

$68 \sqrt{6} + 206$

Step 6

Divide.

$372.5653025$

Step 7

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

$372.6$

Find the Mean 68 square root of 24 , 412

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