Find the Mean 64 , 64 , 68 , 73 , 76 , 78 , 80 , 86 , 88 , 90 , 93

$64$ ,

$68$ ,

$73$ ,

$76$ ,

$78$ ,

$80$ ,

$86$ ,

$88$ ,

$90$ ,

$93$

Step 1

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{64 + 64 + 68 + 73 + 76 + 78 + 80 + 86 + 88 + 90 + 93}{11}$

Step 2

Simplify the numerator.

Add

$64$ and

$64$ .

$\frac{128 + 68 + 73 + 76 + 78 + 80 + 86 + 88 + 90 + 93}{11}$

Add

$128$ and

$68$ .

$\frac{196 + 73 + 76 + 78 + 80 + 86 + 88 + 90 + 93}{11}$

Add

$196$ and

$73$ .

$\frac{269 + 76 + 78 + 80 + 86 + 88 + 90 + 93}{11}$

Add

$269$ and

$76$ .

$\frac{345 + 78 + 80 + 86 + 88 + 90 + 93}{11}$

Add

$345$ and

$78$ .

$\frac{423 + 80 + 86 + 88 + 90 + 93}{11}$

Add

$423$ and

$80$ .

$\frac{503 + 86 + 88 + 90 + 93}{11}$

Add

$503$ and

$86$ .

$\frac{589 + 88 + 90 + 93}{11}$

Add

$589$ and

$88$ .

$\frac{677 + 90 + 93}{11}$

Add

$677$ and

$90$ .

$\frac{767 + 93}{11}$

Add

$767$ and

$93$ .

$\frac{860}{11}$

Step 3

Divide.

$78.\overline{18}$

Step 4

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

$78.2$

Find the Mean 64 , 64 , 68 , 73 , 76 , 78 , 80 , 86 , 88 , 90 , 93

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