Find the Mean 523 , 1414 , 10981 , 23315 , 27936 , 24602 , 14631 , 17264

$523$ , $1414$ , $10981$ , $23315$ , $27936$ , $24602$ , $14631$ , $17264$

Step 1

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{523 + 1414 + 10981 + 23315 + 27936 + 24602 + 14631 + 17264}{8}$

Step 2

Simplify the numerator.

Add $523$ and $1414$ .

$\frac{1937 + 10981 + 23315 + 27936 + 24602 + 14631 + 17264}{8}$

Add $1937$ and $10981$ .

$\frac{12918 + 23315 + 27936 + 24602 + 14631 + 17264}{8}$

Add $12918$ and $23315$ .

$\frac{36233 + 27936 + 24602 + 14631 + 17264}{8}$

Add $36233$ and $27936$ .

$\frac{64169 + 24602 + 14631 + 17264}{8}$

Add $64169$ and $24602$ .

$\frac{88771 + 14631 + 17264}{8}$

Add $88771$ and $14631$ .

$\frac{103402 + 17264}{8}$

Add $103402$ and $17264$ .

$\frac{120666}{8}$

Step 3

Cancel the common factor of $120666$ and $8$ .

Factor $2$ out of $120666$ .

$\frac{2 (60333)}{8}$

Cancel the common factors.

Factor $2$ out of $8$ .

$\frac{2 \cdot 60333}{2 \cdot 4}$

Cancel the common factor.

$\frac{2 \cdot 60333}{2 \cdot 4}$

Rewrite the expression.

$\frac{60333}{4}$

Step 4

Divide.

$15083.25$

Step 5

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

$15083.3$

Find the Mean 523 , 1414 , 10981 , 23315 , 27936 , 24602 , 14631 , 17264

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