Find the Mean 36 , 39 , 40 , 47 , 52 , 55 , 57 , 68 , 68 , 72 , 80

$36$ ,

$39$ ,

$40$ ,

$47$ ,

$52$ ,

$55$ ,

$57$ ,

$68$ ,

$72$ ,

$80$

Step 1

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{36 + 39 + 40 + 47 + 52 + 55 + 57 + 68 + 68 + 72 + 80}{11}$

Step 2

Simplify the numerator.

Add

$36$ and

$39$ .

$\frac{75 + 40 + 47 + 52 + 55 + 57 + 68 + 68 + 72 + 80}{11}$

Add

$75$ and

$40$ .

$\frac{115 + 47 + 52 + 55 + 57 + 68 + 68 + 72 + 80}{11}$

Add

$115$ and

$47$ .

$\frac{162 + 52 + 55 + 57 + 68 + 68 + 72 + 80}{11}$

Add

$162$ and

$52$ .

$\frac{214 + 55 + 57 + 68 + 68 + 72 + 80}{11}$

Add

$214$ and

$55$ .

$\frac{269 + 57 + 68 + 68 + 72 + 80}{11}$

Add

$269$ and

$57$ .

$\frac{326 + 68 + 68 + 72 + 80}{11}$

Add

$326$ and

$68$ .

$\frac{394 + 68 + 72 + 80}{11}$

Add

$394$ and

$68$ .

$\frac{462 + 72 + 80}{11}$

Add

$462$ and

$72$ .

$\frac{534 + 80}{11}$

Add

$534$ and

$80$ .

$\frac{614}{11}$

Step 3

Divide.

$55.\overline{81}$

Step 4

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

$55.8$

Find the Mean 36 , 39 , 40 , 47 , 52 , 55 , 57 , 68 , 68 , 72 , 80

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