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Find the Mean 32 , 60 , 48 , 36

$32$ ,

$60$ ,

$48$ ,

$36$

Step 1

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{32 + 60 + 48 + 36}{4}$

Step 2

Cancel the common factor of

$32 + 60 + 48 + 36$ and

$4$ .

Factor

$4$ out of

$32$ .

$\frac{4 \cdot 8 + 60 + 48 + 36}{4}$

Factor

$4$ out of

$60$ .

$\frac{4 \cdot 8 + 4 \cdot 15 + 48 + 36}{4}$

Factor

$4$ out of

$4 \cdot 8 + 4 \cdot 15$ .

$\frac{4 \cdot (8 + 15) + 48 + 36}{4}$

Factor

$4$ out of

$48$ .

$\frac{4 \cdot (8 + 15) + 4 \cdot 12 + 36}{4}$

Factor

$4$ out of

$4 \cdot (8 + 15) + 4 (12)$ .

$\frac{4 \cdot (8 + 15 + 12) + 36}{4}$

Factor

$4$ out of

$36$ .

$\frac{4 \cdot (8 + 15 + 12) + 4 \cdot 9}{4}$

Factor

$4$ out of

$4 \cdot (8 + 15 + 12) + 4 (9)$ .

$\frac{4 \cdot (8 + 15 + 12 + 9)}{4}$

Cancel the common factors.

Factor

$4$ out of

$4$ .

$\frac{4 \cdot (8 + 15 + 12 + 9)}{4 (1)}$

Cancel the common factor.

$\frac{4 \cdot (8 + 15 + 12 + 9)}{4 \cdot 1}$

Rewrite the expression.

$\frac{8 + 15 + 12 + 9}{1}$

Divide

$8 + 15 + 12 + 9$ by

$1$ .

$8 + 15 + 12 + 9$

$8 + 15 + 12 + 9$

$8 + 15 + 12 + 9$

Step 3

Simplify by adding numbers.

Add

$8$ and

$15$ .

$23 + 12 + 9$

Add

$23$ and

$12$ .

$35 + 9$

Add

$35$ and

$9$ .

$44$

$44$

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