Find the Mean [29,58,15,129,75,22]

$[29, 58, 15, 129, 75, 22]$

Step 1

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{29 + 58 + 15 + 129 + 75 + 22}{6}$

Step 2

Simplify the numerator.

Add

$29$ and

$58$ .

$\frac{87 + 15 + 129 + 75 + 22}{6}$

Add

$87$ and

$15$ .

$\frac{102 + 129 + 75 + 22}{6}$

Add

$102$ and

$129$ .

$\frac{231 + 75 + 22}{6}$

Add

$231$ and

$75$ .

$\frac{306 + 22}{6}$

Add

$306$ and

$22$ .

$\frac{328}{6}$

Step 3

Cancel the common factor of

$328$ and

$6$ .

Factor

$2$ out of

$328$ .

$\frac{2 (164)}{6}$

Cancel the common factors.

Factor

$2$ out of

$6$ .

$\frac{2 \cdot 164}{2 \cdot 3}$

Cancel the common factor.

$\frac{2 \cdot 164}{2 \cdot 3}$

Rewrite the expression.

$\frac{164}{3}$

Step 4

Divide.

$54.\overline{6}$

Step 5

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

$54.7$

Find the Mean [29,58,15,129,75,22]

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