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Find the Mean 192 , 64÷16

$192$ , $64 \div 16$

Step 1

Divide $64$ by $16$ .

$192, 4$

Step 2

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{192 + 4}{2}$

Step 3

Cancel the common factor of $192 + 4$ and $2$ .

Factor $2$ out of $192$ .

$\frac{2 \cdot 96 + 4}{2}$

Factor $2$ out of $4$ .

$\frac{2 \cdot 96 + 2 \cdot 2}{2}$

Factor $2$ out of $2 \cdot 96 + 2 \cdot 2$ .

$\frac{2 \cdot (96 + 2)}{2}$

Cancel the common factors.

Factor $2$ out of $2$ .

$\frac{2 \cdot (96 + 2)}{2 (1)}$

Cancel the common factor.

$\frac{2 \cdot (96 + 2)}{2 \cdot 1}$

Rewrite the expression.

$\frac{96 + 2}{1}$

Divide $96 + 2$ by $1$ .

$96 + 2$

$96 + 2$

$96 + 2$

Step 4

Add $96$ and $2$ .

$98$

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