Find the Mean 12 , 176/24

$12$ ,

$\frac{176}{24}$

Step 1

Cancel the common factor of

$176$ and

$24$ .

Factor

$8$ out of

$176$ .

$12, \frac{8 (22)}{24}$

Cancel the common factors.

Factor

$8$ out of

$24$ .

$12, \frac{8 \cdot 22}{8 \cdot 3}$

Cancel the common factor.

$12, \frac{8 \cdot 22}{8 \cdot 3}$

Rewrite the expression.

$12, \frac{22}{3}$

Step 2

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{12 + \frac{22}{3}}{2}$

Step 3

Cancel the common factor of

$12 + \frac{22}{3}$ and

$2$ .

Factor

$2$ out of

$12$ .

$\frac{2 \cdot 6 + \frac{22}{3}}{2}$

Factor

$2$ out of

$\frac{22}{3}$ .

$\frac{2 \cdot 6 + 2 (\frac{11}{3})}{2}$

Factor

$2$ out of

$2 \cdot 6 + 2 (\frac{11}{3})$ .

$\frac{2 \cdot (6 + \frac{11}{3})}{2}$

Cancel the common factors.

Factor

$2$ out of

$2$ .

$\frac{2 \cdot (6 + \frac{11}{3})}{2 (1)}$

Cancel the common factor.

$\frac{2 \cdot (6 + \frac{11}{3})}{2 \cdot 1}$

Rewrite the expression.

$\frac{6 + \frac{11}{3}}{1}$

Divide

$6 + \frac{11}{3}$ by

$1$ .

$6 + \frac{11}{3}$

Step 4

To write

$6$ as a fraction with a common denominator, multiply by

$\frac{3}{3}$ .

$6 \cdot \frac{3}{3} + \frac{11}{3}$

Step 5

Combine

$6$ and

$\frac{3}{3}$ .

$\frac{6 \cdot 3}{3} + \frac{11}{3}$

Step 6

Combine the numerators over the common denominator.

$\frac{6 \cdot 3 + 11}{3}$

Step 7

Simplify the numerator.

Multiply

$6$ by

$3$ .

$\frac{18 + 11}{3}$

Add

$18$ and

$11$ .

$\frac{29}{3}$

Step 8

Divide.

$9.\overline{6}$

Step 9

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

$9.7$

Find the Mean 12 , 176/24

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