Find the Mean 12 , 176÷24

$12$ ,

$176 \div 24$

Step 1

Rewrite the division as a fraction.

$12, \frac{176}{24}$

Step 2

Cancel the common factor of

$176$ and

$24$ .

Factor

$8$ out of

$176$ .

$12, \frac{8 (22)}{24}$

Cancel the common factors.

Factor

$8$ out of

$24$ .

$12, \frac{8 \cdot 22}{8 \cdot 3}$

Cancel the common factor.

$12, \frac{8 \cdot 22}{8 \cdot 3}$

Rewrite the expression.

$12, \frac{22}{3}$

Step 3

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{12 + \frac{22}{3}}{2}$

Step 4

Cancel the common factor of

$12 + \frac{22}{3}$ and

$2$ .

Factor

$2$ out of

$12$ .

$\frac{2 \cdot 6 + \frac{22}{3}}{2}$

Factor

$2$ out of

$\frac{22}{3}$ .

$\frac{2 \cdot 6 + 2 (\frac{11}{3})}{2}$

Factor

$2$ out of

$2 \cdot 6 + 2 (\frac{11}{3})$ .

$\frac{2 \cdot (6 + \frac{11}{3})}{2}$

Cancel the common factors.

Factor

$2$ out of

$2$ .

$\frac{2 \cdot (6 + \frac{11}{3})}{2 (1)}$

Cancel the common factor.

$\frac{2 \cdot (6 + \frac{11}{3})}{2 \cdot 1}$

Rewrite the expression.

$\frac{6 + \frac{11}{3}}{1}$

Divide

$6 + \frac{11}{3}$ by

$1$ .

$6 + \frac{11}{3}$

Step 5

To write

$6$ as a fraction with a common denominator, multiply by

$\frac{3}{3}$ .

$6 \cdot \frac{3}{3} + \frac{11}{3}$

Step 6

Combine

$6$ and

$\frac{3}{3}$ .

$\frac{6 \cdot 3}{3} + \frac{11}{3}$

Step 7

Combine the numerators over the common denominator.

$\frac{6 \cdot 3 + 11}{3}$

Step 8

Simplify the numerator.

Multiply

$6$ by

$3$ .

$\frac{18 + 11}{3}$

Add

$18$ and

$11$ .

$\frac{29}{3}$

Step 9

Divide.

$9.\overline{6}$

Step 10

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

$9.7$

Find the Mean 12 , 176÷24

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