Find the Mean 0 , 72 , 75 , 75 , 83 , 83 , 83 , 91

$0$ ,

$72$ ,

$75$ ,

$83$ ,

$91$

Step 1

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{0 + 72 + 75 + 75 + 83 + 83 + 83 + 91}{8}$

Step 2

Simplify the numerator.

Add

$0$ and

$72$ .

$\frac{72 + 75 + 75 + 83 + 83 + 83 + 91}{8}$

Add

$72$ and

$75$ .

$\frac{147 + 75 + 83 + 83 + 83 + 91}{8}$

Add

$147$ and

$75$ .

$\frac{222 + 83 + 83 + 83 + 91}{8}$

Add

$222$ and

$83$ .

$\frac{305 + 83 + 83 + 91}{8}$

Add

$305$ and

$83$ .

$\frac{388 + 83 + 91}{8}$

Add

$388$ and

$83$ .

$\frac{471 + 91}{8}$

Add

$471$ and

$91$ .

$\frac{562}{8}$

Step 3

Cancel the common factor of

$562$ and

$8$ .

Factor

$2$ out of

$562$ .

$\frac{2 (281)}{8}$

Cancel the common factors.

Factor

$2$ out of

$8$ .

$\frac{2 \cdot 281}{2 \cdot 4}$

Cancel the common factor.

$\frac{2 \cdot 281}{2 \cdot 4}$

Rewrite the expression.

$\frac{281}{4}$

Step 4

Divide.

$70.25$

Step 5

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

$70.3$

Find the Mean 0 , 72 , 75 , 75 , 83 , 83 , 83 , 91

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