Find the Mean 0 , 5^-3*2^-3

$0$ , $5^{- 3} \cdot 2^{- 3}$

Step 1

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$0, \frac{1}{5^{3}} \cdot 2^{- 3}$

Step 2

Raise $5$ to the power of $3$ .

$0, \frac{1}{125} \cdot 2^{- 3}$

Step 3

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$0, \frac{1}{125} \cdot \frac{1}{2^{3}}$

Step 4

Combine.

$0, \frac{1 \cdot 1}{125 \cdot 2^{3}}$

Step 5

Simplify the expression.

Multiply $1$ by $1$ .

$0, \frac{1}{125 \cdot 2^{3}}$

Raise $2$ to the power of $3$ .

$0, \frac{1}{125 \cdot 8}$

Multiply $125$ by $8$ .

$0, \frac{1}{1000}$

Step 6

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{0 + \frac{1}{1000}}{2}$

Step 7

Add $0$ and $\frac{1}{1000}$ .

$\frac{\frac{1}{1000}}{2}$

Step 8

Multiply the numerator by the reciprocal of the denominator.

$\frac{1}{1000} \cdot \frac{1}{2}$

Step 9

Multiply $\frac{1}{1000} \cdot \frac{1}{2}$ .

Multiply $\frac{1}{1000}$ by $\frac{1}{2}$ .

$\frac{1}{1000 \cdot 2}$

Multiply $1000$ by $2$ .

$\frac{1}{2000}$

Step 10

Divide.

$0.0005$

Step 11

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

$0$

Find the Mean 0 , 5^-3*2^-3

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