Find the Mean 0 , 25.10^13

$0$ , ${25.1}^{13}$

Step 1

Raise $25.1$ to the power of $13$ .

$0, 1569489372320390000$

Step 2

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{0 + 1569489372320390000}{2}$

Step 3

Cancel the common factor of $0 + 1569489372320390000$ and $2$ .

Factor $2$ out of $0$ .

$\frac{2 \cdot 0 + 1569489372320390000}{2}$

Factor $2$ out of $1569489372320390000$ .

$\frac{2 \cdot 0 + 2 \cdot 784744686160195000}{2}$

Factor $2$ out of $2 \cdot 0 + 2 \cdot 784744686160195000$ .

$\frac{2 \cdot (0 + 784744686160195000)}{2}$

Cancel the common factors.

Factor $2$ out of $2$ .

$\frac{2 \cdot (0 + 784744686160195000)}{2 (1)}$

Cancel the common factor.

$\frac{2 \cdot (0 + 784744686160195000)}{2 \cdot 1}$

Rewrite the expression.

$\frac{0 + 784744686160195000}{1}$

Divide $0 + 784744686160195000$ by $1$ .

$0 + 784744686160195000$

Step 4

Add $0$ and $784744686160195000$ .

$784744686160195000$

Step 5

Divide.

$7.84744686 \times 10^{17}$