Find the Intersection of the Inequalities 2*(-3y)<=12 , y<-3

$2 \cdot (- 3 y) \leq 12$ , $y < - 3$

Step 1

Simplify the first inequality.

Multiply $- 3$ by $2$ .

$- 6 \cdot y \leq 12$ and $y < - 3$

Divide each term in $(- 6 \cdot y) \leq 12$ by $- 6$ and simplify.

Divide each term in $(- 6 \cdot y) \leq 12$ by $- 6$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 6 \cdot y}{- 6} \geq \frac{12}{- 6}$ and $y < - 3$

Simplify the left side.

Cancel the common factor of $- 6$ .

Cancel the common factor.

$\frac{- 6 \cdot y}{- 6} \geq \frac{12}{- 6}$ and $y < - 3$

Divide $y$ by $1$ .

$y \geq \frac{12}{- 6}$ and $y < - 3$

Simplify the right side.

Divide $12$ by $- 6$ .

$y \geq - 2$ and $y < - 3$

Step 2

The intersection consists of the elements that are contained in both intervals.

No solution

Find the Intersection of the Inequalities 2*(-3y)<=12 , y<-3

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