Find the Intersection of the Inequalities 2*(-3y)<=12 , y<-3

$2 \cdot (- 3 y) \leq 12$ ,

$y < - 3$

Step 1

Simplify the first inequality.

Multiply

$- 3$ by

$2$ .

$- 6 \cdot y \leq 12$ and

$y < - 3$

Divide each term in

$(- 6 \cdot y) \leq 12$ by

$- 6$ and simplify.

Divide each term in

$(- 6 \cdot y) \leq 12$ by

$- 6$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 6 \cdot y}{- 6} \geq \frac{12}{- 6}$ and

$y < - 3$

Simplify the left side.

Cancel the common factor of

$- 6$ .

Cancel the common factor.

$\frac{- 6 \cdot y}{- 6} \geq \frac{12}{- 6}$ and

$y < - 3$

Divide

$y$ by

$1$ .

$y \geq \frac{12}{- 6}$ and

$y < - 3$

$y \geq \frac{12}{- 6}$ and

$y < - 3$

$y \geq \frac{12}{- 6}$ and

$y < - 3$

Simplify the right side.

Divide

$12$ by

$- 6$ .

$y \geq - 2$ and

$y < - 3$

$y \geq - 2$ and

$y < - 3$

$y \geq - 2$ and

$y < - 3$

$y \geq - 2$ and

$y < - 3$

Step 2

The intersection consists of the elements that are contained in both intervals.

No solution

Find the Intersection of the Inequalities 2*(-3y)<=12 , y<-3

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