Find the Area triangle (12)(9)

 $\begin{array}{r} b = & 9 \\ h = & 12 \end{array}$

Step 1

The area of a triangle is equal to $\frac{1}{2}$ the base times the height.

$\frac{1}{2} \cdot (b a s e) \cdot (h e i g h t)$

Step 2

Substitute the values of the base $b = 9$ and height $h = 12$ into the formula for the area of a triangle.

$\frac{1}{2} \cdot 9 \cdot 12$

Step 3

Combine $\frac{1}{2}$ and $9$ .

$\frac{9}{2} \cdot 12$

Step 4

Cancel the common factor of $2$ .

Factor $2$ out of $12$ .

$\frac{9}{2} \cdot (2 (6))$

Cancel the common factor.

$\frac{9}{2} \cdot (2 \cdot 6)$

Rewrite the expression.

$9 \cdot 6$

Step 5

Multiply $9$ by $6$ .

$54$