Find the Area triangle (10)(13)

 $\begin{array}{r} b = & 13 \\ h = & 10 \end{array}$

Step 1

The area of a triangle is equal to $\frac{1}{2}$ the base times the height.

$\frac{1}{2} \cdot (b a s e) \cdot (h e i g h t)$

Step 2

Substitute the values of the base $b = 13$ and height $h = 10$ into the formula for the area of a triangle.

$\frac{1}{2} \cdot 13 \cdot 10$

Step 3

Combine $\frac{1}{2}$ and $13$ .

$\frac{13}{2} \cdot 10$

Step 4

Cancel the common factor of $2$ .

Factor $2$ out of $10$ .

$\frac{13}{2} \cdot (2 (5))$

Cancel the common factor.

$\frac{13}{2} \cdot (2 \cdot 5)$

Rewrite the expression.

$13 \cdot 5$

Step 5

Multiply $13$ by $5$ .

$65$