Find the Area trapezoid (9.2)(6.8)(7.7)

 $\begin{array}{r} b_{1} = & 9.2 \\ b_{2} = & 6.8 \\ h = & 7.7 \end{array}$

Step 1

The area of a trapezoid is equal to $\frac{1}{2}$ times the height times the sum of the bases $b_{1} + b_{2}$ .

$\frac{1}{2} \cdot (h e i g h t) \cdot (b_{1} + b_{2})$

Step 2

Substitute the values of the height $h = 7.7$ and bases ( $b_{1} = 9.2$ and $b_{2} = 6.8$ ) into the formula for the area of a trapezoid.

$\frac{1}{2} \cdot 7.7 \cdot (9.2 + 6.8)$

Step 3

Combine $\frac{1}{2}$ and $7.7$ .

$\frac{7.7}{2} \cdot (9.2 + 6.8)$

Step 4

Simplify the expression.

Divide $7.7$ by $2$ .

$3.85 \cdot (9.2 + 6.8)$

Add $9.2$ and $6.8$ .

$3.85 \cdot 16$

Multiply $3.85$ by $16$ .

$61.6$