Find the Area trapezoid (5)(6)(10)

 $\begin{array}{r} b_{1} = & 5 \\ b_{2} = & 6 \\ h = & 10 \end{array}$

Step 1

The area of a trapezoid is equal to $\frac{1}{2}$ times the height times the sum of the bases $b_{1} + b_{2}$ .

$\frac{1}{2} \cdot (h e i g h t) \cdot (b_{1} + b_{2})$

Step 2

Substitute the values of the height $h = 10$ and bases ( $b_{1} = 5$ and $b_{2} = 6$ ) into the formula for the area of a trapezoid.

$\frac{1}{2} \cdot 10 \cdot (5 + 6)$

Step 3

Cancel the common factor of $2$ .

Factor $2$ out of $10$ .

$\frac{1}{2} \cdot (2 (5)) \cdot (5 + 6)$

Cancel the common factor.

$\frac{1}{2} \cdot (2 \cdot 5) \cdot (5 + 6)$

Rewrite the expression.

$5 \cdot (5 + 6)$

Step 4

Simplify the expression.

Add $5$ and $6$ .

$5 \cdot 11$

Multiply $5$ by $11$ .

$55$