Find the Area trapezoid (5)(3)(7)

 $\begin{array}{r} b_{1} = & 5 \\ b_{2} = & 3 \\ h = & 7 \end{array}$

Step 1

The area of a trapezoid is equal to $\frac{1}{2}$ times the height times the sum of the bases $b_{1} + b_{2}$ .

$\frac{1}{2} \cdot (h e i g h t) \cdot (b_{1} + b_{2})$

Step 2

Substitute the values of the height $h = 7$ and bases ( $b_{1} = 5$ and $b_{2} = 3$ ) into the formula for the area of a trapezoid.

$\frac{1}{2} \cdot 7 \cdot (5 + 3)$

Step 3

Combine $\frac{1}{2}$ and $7$ .

$\frac{7}{2} \cdot (5 + 3)$

Step 4

Add $5$ and $3$ .

$\frac{7}{2} \cdot 8$

Step 5

Cancel the common factor of $2$ .

Factor $2$ out of $8$ .

$\frac{7}{2} \cdot (2 (4))$

Cancel the common factor.

$\frac{7}{2} \cdot (2 \cdot 4)$

Rewrite the expression.

$7 \cdot 4$

Step 6

Multiply $7$ by $4$ .

$28$