Find the Area trapezoid (5)(2)(6)

 $\begin{array}{r} b_{1} = & 5 \\ b_{2} = & 2 \\ h = & 6 \end{array}$

Step 1

The area of a trapezoid is equal to $\frac{1}{2}$ times the height times the sum of the bases $b_{1} + b_{2}$ .

$\frac{1}{2} \cdot (h e i g h t) \cdot (b_{1} + b_{2})$

Step 2

Substitute the values of the height $h = 6$ and bases ( $b_{1} = 5$ and $b_{2} = 2$ ) into the formula for the area of a trapezoid.

$\frac{1}{2} \cdot 6 \cdot (5 + 2)$

Step 3

Cancel the common factor of $2$ .

Factor $2$ out of $6$ .

$\frac{1}{2} \cdot (2 (3)) \cdot (5 + 2)$

Cancel the common factor.

$\frac{1}{2} \cdot (2 \cdot 3) \cdot (5 + 2)$

Rewrite the expression.

$3 \cdot (5 + 2)$

Step 4

Simplify the expression.

Add $5$ and $2$ .

$3 \cdot 7$

Multiply $3$ by $7$ .

$21$