Find the Area trapezoid (11)(2)(17)



$\begin{array}{r} b_{1} = & 11 \\ b_{2} = & 2 \\ h = & 17 \end{array}$

Step 1

The area of a trapezoid is equal to

$\frac{1}{2}$ times the height times the sum of the bases

$b_{1} + b_{2}$ .

$\frac{1}{2} \cdot (h e i g h t) \cdot (b_{1} + b_{2})$

Step 2

Substitute the values of the height

$h = 17$ and bases (

$b_{1} = 11$ and

$b_{2} = 2$ ) into the formula for the area of a trapezoid.

$\frac{1}{2} \cdot 17 \cdot (11 + 2)$

Step 3

Combine

$\frac{1}{2}$ and

$17$ .

$\frac{17}{2} \cdot (11 + 2)$

Step 4

Add

$11$ and

$2$ .

$\frac{17}{2} \cdot 13$

Step 5

Multiply

$\frac{17}{2} \cdot 13$ .

Combine

$\frac{17}{2}$ and

$13$ .

$\frac{17 \cdot 13}{2}$

Multiply

$17$ by

$13$ .

$\frac{221}{2}$

Step 6

The result can be shown in multiple forms.

Exact Form:

$\frac{221}{2}$

Decimal Form:

$110.5$

Mixed Number Form:

$110 \frac{1}{2}$