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Evaluate (-6)^2-3|2-7(5+2)|

${(- 6)}^{2} - 3 | 2 - 7 (5 + 2) |$

Step 1

Simplify each term.

Raise $- 6$ to the power of $2$ .

$36 - 3 | 2 - 7 (5 + 2) |$

Simplify each term.

Add $5$ and $2$ .

$36 - 3 | 2 - 7 \cdot 7 |$

Multiply $- 7$ by $7$ .

$36 - 3 | 2 - 49 |$

$36 - 3 | 2 - 49 |$

Subtract $49$ from $2$ .

$36 - 3 | - 47 |$

The absolute value is the distance between a number and zero. The distance between $- 47$ and $0$ is $47$ .

$36 - 3 \cdot 47$

Multiply $- 3$ by $47$ .

$36 - 141$

$36 - 141$

Step 2

Subtract $141$ from $36$ .

$- 105$

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