Evaluate (-48*5/6)÷(-4)+|9-3(5+2)|

$- 48 \cdot \frac{5}{6} \div (- 4) + | 9 - 3 (5 + 2) |$

Step 1

Simplify each term.

Rewrite the division as a fraction.

$\frac{- 48 \cdot \frac{5}{6}}{- 4} + | 9 - 3 (5 + 2) |$

Cancel the common factor of $- 48$ and $- 4$ .

Factor $- 4$ out of $- 48 \cdot \frac{5}{6}$ .

$\frac{- 4 (12 \cdot \frac{5}{6})}{- 4} + | 9 - 3 (5 + 2) |$

Cancel the common factors.

Factor $- 4$ out of $- 4$ .

$\frac{- 4 (12 \cdot \frac{5}{6})}{- 4 (1)} + | 9 - 3 (5 + 2) |$

Cancel the common factor.

$\frac{- 4 (12 \cdot \frac{5}{6})}{- 4 \cdot 1} + | 9 - 3 (5 + 2) |$

Rewrite the expression.

$\frac{12 \cdot \frac{5}{6}}{1} + | 9 - 3 (5 + 2) |$

Divide $12 \cdot \frac{5}{6}$ by $1$ .

$12 \cdot \frac{5}{6} + | 9 - 3 (5 + 2) |$

Cancel the common factor of $6$ .

Factor $6$ out of $12$ .

$6 (2) \cdot \frac{5}{6} + | 9 - 3 (5 + 2) |$

Cancel the common factor.

$6 \cdot 2 \cdot \frac{5}{6} + | 9 - 3 (5 + 2) |$

Rewrite the expression.

$2 \cdot 5 + | 9 - 3 (5 + 2) |$

Multiply $2$ by $5$ .

$10 + | 9 - 3 (5 + 2) |$

Simplify each term.

Add $5$ and $2$ .

$10 + | 9 - 3 \cdot 7 |$

Multiply $- 3$ by $7$ .

$10 + | 9 - 21 |$

Subtract $21$ from $9$ .

$10 + | - 12 |$

The absolute value is the distance between a number and zero. The distance between $- 12$ and $0$ is $12$ .

$10 + 12$

Step 2

Add $10$ and $12$ .

$22$