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Evaluate 4000(1+(0.035)(9/12))

$4000 (1 + (0.035) (\frac{9}{12}))$

Step 1

Simplify each term.

Cancel the common factor of $9$ and $12$ .

Factor $3$ out of $9$ .

$4000 (1 + 0.035 \frac{3 (3)}{12})$

Cancel the common factors.

Factor $3$ out of $12$ .

$4000 (1 + 0.035 \frac{3 \cdot 3}{3 \cdot 4})$

Cancel the common factor.

$4000 (1 + 0.035 \frac{3 \cdot 3}{3 \cdot 4})$

Rewrite the expression.

$4000 (1 + 0.035 (\frac{3}{4}))$

$4000 (1 + 0.035 (\frac{3}{4}))$

$4000 (1 + 0.035 (\frac{3}{4}))$

Multiply $0.035 (\frac{3}{4})$ .

Combine $0.035$ and $\frac{3}{4}$ .

$4000 (1 + \frac{0.035 \cdot 3}{4})$

Multiply $0.035$ by $3$ .

$4000 (1 + \frac{0.105}{4})$

$4000 (1 + \frac{0.105}{4})$

Divide $0.105$ by $4$ .

$4000 (1 + 0.02625)$

$4000 (1 + 0.02625)$

Step 2

Simplify the expression.

Add $1$ and $0.02625$ .

$4000 \cdot 1.02625$

Multiply $4000$ by $1.02625$ .

$4105$

$4105$

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