Evaluate (4+34÷17-6)^3+3

${(4 + 34 \div 17 - 6)}^{3} + 3$

Step 1

Simplify each term.

Find the common denominator.

Write $4$ as a fraction with denominator $1$ .

${(\frac{4}{1} + 34 \div 17 - 6)}^{3} + 3$

Multiply $\frac{4}{1}$ by $\frac{17}{17}$ .

${(\frac{4}{1} \cdot \frac{17}{17} + 34 \div 17 - 6)}^{3} + 3$

Multiply $\frac{4}{1}$ by $\frac{17}{17}$ .

${(\frac{4 \cdot 17}{17} + 34 \div 17 - 6)}^{3} + 3$

Write $- 6$ as a fraction with denominator $1$ .

${(\frac{4 \cdot 17}{17} + 34 \div 17 + \frac{- 6}{1})}^{3} + 3$

Multiply $\frac{- 6}{1}$ by $\frac{17}{17}$ .

${(\frac{4 \cdot 17}{17} + 34 \div 17 + \frac{- 6}{1} \cdot \frac{17}{17})}^{3} + 3$

Multiply $\frac{- 6}{1}$ by $\frac{17}{17}$ .

${(\frac{4 \cdot 17}{17} + 34 \div 17 + \frac{- 6 \cdot 17}{17})}^{3} + 3$

Combine the numerators over the common denominator.

${(\frac{4 \cdot 17 + 34 - 6 \cdot 17}{17})}^{3} + 3$

Simplify each term.

Multiply $4$ by $17$ .

${(\frac{68 + 34 - 6 \cdot 17}{17})}^{3} + 3$

Multiply $- 6$ by $17$ .

${(\frac{68 + 34 - 102}{17})}^{3} + 3$

Add $68$ and $34$ .

${(\frac{102 - 102}{17})}^{3} + 3$

Subtract $102$ from $102$ .

${(\frac{0}{17})}^{3} + 3$

Divide $0$ by $17$ .

$0^{3} + 3$

Raising $0$ to any positive power yields $0$ .

$0 + 3$

Step 2

Add $0$ and $3$ .

$3$