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Evaluate 2 square root of 6+3 square root of 24

$2 \sqrt{6} + 3 \sqrt{24}$

Step 1

Simplify each term.

Rewrite $24$ as $2^{2} \cdot 6$ .

Factor $4$ out of $24$ .

$2 \sqrt{6} + 3 \sqrt{4 (6)}$

Rewrite $4$ as $2^{2}$ .

$2 \sqrt{6} + 3 \sqrt{2^{2} \cdot 6}$

$2 \sqrt{6} + 3 \sqrt{2^{2} \cdot 6}$

Pull terms out from under the radical.

$2 \sqrt{6} + 3 (2 \sqrt{6})$

Multiply $2$ by $3$ .

$2 \sqrt{6} + 6 \sqrt{6}$

$2 \sqrt{6} + 6 \sqrt{6}$

Step 2

Add $2 \sqrt{6}$ and $6 \sqrt{6}$ .

$8 \sqrt{6}$

Step 3

The result can be shown in multiple forms.

Exact Form:

$8 \sqrt{6}$

Decimal Form:

$19.59591794 \dots$

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