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Evaluate (-2)^2+26÷(-8+6)*2-(-10)-2^2

${(- 2)}^{2} + 26 \div (- 8 + 6) \cdot 2 - (- 10) - 2^{2}$

Step 1

Simplify each term.

Raise $- 2$ to the power of $2$ .

$4 + 26 \div (- 8 + 6) \cdot 2 - (- 10) - 2^{2}$

Add $- 8$ and $6$ .

$4 + 26 \div (- 2) \cdot 2 - (- 10) - 2^{2}$

Divide $26$ by $- 2$ .

$4 - 13 \cdot 2 - (- 10) - 2^{2}$

Multiply $- 13$ by $2$ .

$4 - 26 - (- 10) - 2^{2}$

Multiply $- 1$ by $- 10$ .

$4 - 26 + 10 - 2^{2}$

Raise $2$ to the power of $2$ .

$4 - 26 + 10 - 1 \cdot 4$

Multiply $- 1$ by $4$ .

$4 - 26 + 10 - 4$

$4 - 26 + 10 - 4$

Step 2

Simplify by adding and subtracting.

Subtract $26$ from $4$ .

$- 22 + 10 - 4$

Add $- 22$ and $10$ .

$- 12 - 4$

Subtract $4$ from $- 12$ .

$- 16$

$- 16$

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