Evaluate (-16/7)/(2^2)

$\frac{- \frac{16}{7}}{2^{2}}$

Step 1

Multiply the numerator by the reciprocal of the denominator.

$- \frac{16}{7} \cdot \frac{1}{2^{2}}$

Step 2

Raise $2$ to the power of $2$ .

$- \frac{16}{7} \cdot \frac{1}{4}$

Step 3

Cancel the common factor of $4$ .

Move the leading negative in $- \frac{16}{7}$ into the numerator.

$\frac{- 16}{7} \cdot \frac{1}{4}$

Factor $4$ out of $- 16$ .

$\frac{4 (- 4)}{7} \cdot \frac{1}{4}$

Cancel the common factor.

$\frac{4 \cdot - 4}{7} \cdot \frac{1}{4}$

Rewrite the expression.

$\frac{- 4}{7}$

Step 4

Move the negative in front of the fraction.

$- \frac{4}{7}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$- \frac{4}{7}$

Decimal Form:

$- 0.\overline{571428}$